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Radius of this circle?

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Old 11 April 2012, 04:33 PM
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David Lock
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Default Radius of this circle?

Say you cut the top of a circle off and drew a line underneath. Say this line was x long.

You then had a vertical line from the middle of the bottom line and it hit the top of the circle at a distance of say y.

So what is the radius of the circle please?

dl

Last edited by David Lock; 11 April 2012 at 04:34 PM.
Old 11 April 2012, 05:16 PM
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Maz
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You're going to have to draw a picture.
Old 11 April 2012, 05:18 PM
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wayne9t9
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I think I need a picture for that one
Old 11 April 2012, 05:32 PM
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JTaylor
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Originally Posted by David Lock
Say you cut the top of a circle off and drew a line underneath. Say this line was x long.

You then had a vertical line from the middle of the bottom line and it hit the top of the circle at a distance of say y.

So what is the radius of the circle please?

dl
Here you go, David.

http://www.mathopenref.com/arcradius.html
Old 11 April 2012, 05:36 PM
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richiewong
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Probably have use this in it somewhere no doubt;

Old 11 April 2012, 07:29 PM
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David Lock
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Mr Taylor, thank you.

Mr Wong, I'm trying the think what you can do with that pie

PS. So I can put a house name of front of my gate to match curved top of gate

david
Old 11 April 2012, 10:07 PM
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boomer
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Originally Posted by richiewong
Probably have use this in it somewhere no doubt;

mmmmmmmm, Hollands Meat Pies

Got a couple in my freezer now - just in case i get hungry

mb
Old 12 April 2012, 06:14 AM
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RobsyUK
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So what's the answer
Old 12 April 2012, 07:59 AM
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JTaylor
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Originally Posted by RobsyUK
So what's the answer
#4 has something called a link and that has been preceded by the words here, you, go and David to indicate that within said 'link' lies a resolution to the OP's enquiry. HTH.
Old 12 April 2012, 09:49 AM
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SkullFudge
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The radius is commonly half the diameter length
Old 12 April 2012, 10:31 AM
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David Lock
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Originally Posted by SkullFudge
The radius is commonly half the diameter length

Was that an A level question?

dl
Old 12 April 2012, 01:40 PM
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speedking
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Bored at lunch.

Proof of the link solution.

The shape described is a segment. Let x be the horizontal dimension of the segment and y the vertical.

A line from the centre to one end of the horizontal = r in length.
Half the horizontal = x/2.
A line from the centre to the x line has length r-y.

So by Pythagoras:

r² = (r-y)²+(x/2)²
r² = r²-2ry+y²+x²/4
cancel the r²
0 = -2ry+y²+x²/4
2ry = y²+x²/4
divide all by 2y
r = y/2+x²/8y

Last edited by speedking; 12 April 2012 at 03:00 PM. Reason: convert to x,y as question.
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