approx how much would this weigh
28 September 2007, 09:18 PM
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approx how much would this weigh
If i have a simple water container with 25 litres of fluid inside, how much do you think it would weigh?
need to send some barrels down south and have no idea about the wieght of them
need to send some barrels down south and have no idea about the wieght of them
So if he's sending shandy down to us, what will that weigh?
)
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28 September 2007, 11:47 PM
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29 September 2007, 05:01 PM
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wont matter because you will resolve all your *ing and /ing according to the brackets before applting the +ing. The other brackets are to clarify if it is (4/5)*25 which is 20 or 4/(5*25) which is 0.32.... can I just add.......
p.s. - but is does have to be at 1 atm
p.s..s
Last edited by fast bloke; 29 September 2007 at 05:03 PM.
29 September 2007, 07:04 PM
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But you had
(4/5)/25 = 0.032
+
rd(1/5)/25 = rd(0.008) which even if the extra product is plutonium, would mean the entire contents of the drum would weigh less than a couple of mars bars.
My point was the intermediate /s should be *s which you updated in the second post 
(4/5)/25 = 0.032
+
rd(1/5)/25 = rd(0.008) which even if the extra product is plutonium, would mean the entire contents of the drum would weigh less than a couple of mars bars.
29 September 2007, 07:47 PM
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30 September 2007, 12:19 AM
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But you had
(4/5)/25 = 0.032
+
rd(1/5)/25 = rd(0.008) which even if the extra product is plutonium, would mean the entire contents of the drum would weigh less than a couple of mars bars.
My point was the intermediate /s should be *s which you updated in the second post
(4/5)/25 = 0.032
+
rd(1/5)/25 = rd(0.008) which even if the extra product is plutonium, would mean the entire contents of the drum would weigh less than a couple of mars bars.
My point was the intermediate /s should be *s which you updated in the second post
Are you expecting me to be stupid all the time?
30 September 2007, 02:58 PM
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i figured it easier to ask about 25 as i was unsure at the time how many barrels i wanted to send, and it looks like i might have been right judging by the "star trek" response
30 September 2007, 05:30 PM
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You're overly complicating it.
It will be 20kg+5*rd+containor weight. (well, twice as much now )
Why mess around with 1/5ths when you know it's 20L of water and 5Litres of the other stuff.
Isn't water 1Kg/L at ISO conditions, which I thought was 20DegsC?
It will be 20kg+5*rd+containor weight. (well, twice as much now
)Why mess around with 1/5ths when you know it's 20L of water and 5Litres of the other stuff.
Isn't water 1Kg/L at ISO conditions, which I thought was 20DegsC?
30 September 2007, 05:32 PM
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For clarity... we are talking about these containers being located on planet earth and not some other planet with different gravitational forces? 
30 September 2007, 06:17 PM
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