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Old 16 November 2006, 10:03 PM
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Kieran_Burns
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Default Interesting Comparison

Interesting comparison
If you consider that there has been an average of 160,000 troops in the Iraq theatre of operations during the last 22 months, and a total of 2,112 deaths, it translates into a firearm death rate of 60 per 100,000 soldiers.

The death from gunshot rate in Washington D.C. is 80.6 per 100,000 for the same period. That means that a person is about 25% more likely to be shot and killed in the U.S. capital (which has some of the strictest gun control laws in the nation), than in Iraq.

Conclusion: The U.S. should pull out of Washington.
Old 16 November 2006, 10:12 PM
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Suresh
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Old 17 November 2006, 08:11 AM
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CrisPDuk
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That actually surprised me, I thought the rate in Washington would be higher.

I bet if you do the same calculation for Detroit you'd be into three figures
Old 17 November 2006, 04:12 PM
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Kieran_Burns
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Do you think this is why the US invades other countries? It's safer....
Old 17 November 2006, 05:21 PM
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BlkKnight
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This post got me thinking.

It's a hoax I think. . .

Original calculations
100000/160000*100 = 62.5%

2112 *0.625 = 1320

1320 / 22 = 60 deaths per month


total friendly troop in Iraq

I'm not sure where the 2112 came from - After looking about the
I make it 1802 over a 24 month period (2004-2005):

1802*0.625= 1126

1126/24 = 47 DMP

I just can't get the Washington DC figures to add up.

If 80.6 (out of 100,000) people die a month due to fire-arms, that's almost a 1% chance you'll die over a one year period due to a gun related crime. Please verify where you got that figure from.
Old 17 November 2006, 05:28 PM
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WHEELSHOP0_0
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I did read somewhere that one of the most dangerous zip codes (post code) to live in is in the one mile radius of the Whitehouse.
Given the choice I would still rather go there than Iraq
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