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Old 24 April 2005, 10:46 PM
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paulwrxboro
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Smile Whats the answer to this

a farmer keeps cows and chickens if there are 81 heads and 252 legs how many cows and chickens are there

please give me the answer and how to work it out
Old 24 April 2005, 10:51 PM
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warrenm2
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45 cows / 36 chickens
Old 24 April 2005, 10:55 PM
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warrenm2
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let x be number of cows and y be number of chickens

we know that

xCows +yChickens = 81 (1)

and

4xCows + 2yChickens = 252 (2) (ie cows have 4 legs, chickens 2 and the total is 252 legs)

from equ 1 multiply both sides by 2 gives

2xCows + 2yChickens = 162 (3)

subtract equ (3) from equ (2) gives 2xCows = 90 therefore x = 45, substitute in and get y

Hope that helps!
Old 24 April 2005, 11:00 PM
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Bubba po
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That's the right answer. Not sure how he got it, though.

The number 9 has something to do with it.

Ah! simultaneous equations!


I remember those, vaguely.
Old 24 April 2005, 11:03 PM
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paulwrxboro
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Cheers that question was set for my 11 year old son at junior school as part of his homework and i have been sat for 10 mins tryin to work it out lol
Old 24 April 2005, 11:07 PM
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warrenm2
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back to school for you matey!
Old 24 April 2005, 11:11 PM
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paulwrxboro
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i neva went the fist time but it neva affected mee
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