85meg movie of R1 chasing Porsche round the Nurburgring
14 December 2004, 06:39 PM
#1
85meg movie of R1 chasing Porsche round the Nurburgring
Last edited by matty01; 14 December 2004 at 06:41 PM. Reason: Err ... link would be good... :rolleyes:
14 December 2004, 10:44 PM
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Ok, somewhere this must be wrong..
Someone correct me..
1Mb = 1024*1024b = 1048576b
*85 = 89128960b
28.8kbps = 28.8*1024bps = 29491.2bps
therefore 89128960/29491.2 = 3022.2 s
(3022.2/60)/60 = 50.37 mins
If only you could download at 28.8kbps
In reality it's more like 2.5kbps so therefore download time is approximately...
9 1/2 Hours
Hmmm 2hr dial-up before disconnection on Freeserve. Don't think I'll bother.
Was it a good video?
Someone correct me..
1Mb = 1024*1024b = 1048576b
*85 = 89128960b
28.8kbps = 28.8*1024bps = 29491.2bps
therefore 89128960/29491.2 = 3022.2 s
(3022.2/60)/60 = 50.37 mins
If only you could download at 28.8kbps
In reality it's more like 2.5kbps so therefore download time is approximately...
9 1/2 Hours
Hmmm 2hr dial-up before disconnection on Freeserve. Don't think I'll bother.
Was it a good video?
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15 December 2004, 08:54 AM
#10
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Join Date: Aug 2003
Location: Epsom
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Originally Posted by Jap2Scrap
Ok, somewhere this must be wrong..
Someone correct me..
1Mb = 1024*1024b = 1048576b
*85 = 89128960b
28.8kbps = 28.8*1024bps = 29491.2bps
therefore 89128960/29491.2 = 3022.2 s
(3022.2/60)/60 = 50.37 mins
If only you could download at 28.8kbps
In reality it's more like 2.5kbps so therefore download time is approximately...
9 1/2 Hours
Hmmm 2hr dial-up before disconnection on Freeserve. Don't think I'll bother.
Was it a good video?
Someone correct me..
1Mb = 1024*1024b = 1048576b
*85 = 89128960b
28.8kbps = 28.8*1024bps = 29491.2bps
therefore 89128960/29491.2 = 3022.2 s
(3022.2/60)/60 = 50.37 mins
If only you could download at 28.8kbps
In reality it's more like 2.5kbps so therefore download time is approximately...
9 1/2 Hours
Hmmm 2hr dial-up before disconnection on Freeserve. Don't think I'll bother.
Was it a good video?
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