Buzzer

Help needed please

I have got my hands on two new phones, one is a Motorola V300 (on T Mobile) The other is a Motorola V525 (On Vodafone). I had no choice of the network but i know my kids want a PAYG O2 sim card with the free texts thingy

I'm giving them to my kids for their birthdays which are both end of the month

Can i, or does someone know if i can unlock these to any network without taking them to a "specialist"

BTW I know NOTHING about mobile phones other than you dial a number and it rings

Freak

have a mooch round here: http://www.unlockme.co.uk

jaycee

You need a clip to unlock motorola phones.
Try your local phone shop, they should do it for a tenner.

Jason

gsm1

Yep, the unlocking clip for V series models is around. Try an independent retailer but one that has the equipment on site.

Buzzer

Hi Jayce

I asked them and they said because they were specific phones for the network providers, it was against their policy to unlock them

There is a bloke who can do it but as you say charges a tenner to unlock. Just thought i could get away with £20.00 tbh, but if i need a "clip" then spose i'll have to

Cheers thanks


BTW thanks for that freak it will come in handy that site

Brendan Hughes

OK, just to prove search works, I've tagged on the bottom of this thread rather than starting a new one

Is it easy to unlock a Sony Ericsson T630? I'd like to buy one in the next few days, but they aren't available on my network in Portugal, only for another network.

I'm sure this is a stupid question and the answer's Yes, but it would be even stupider if I bought one and then found out the answer was No

Thanks

Brendan

Brendan Hughes

...pur-leeeeease?

jaycee

Brendan, with the right equipment it can be unlocked. It's not as simple as unlocking a Nokia phone though and it needs some hardware plugging into the bottom of it to remove the 4 locks.

Jason

Brendan Hughes

Thanks jaycee I'll jump to the conclusion that someone in Portugal can do it, but perhaps I can just ring around for a few quotes first.