Maths Question
#1
I have a roll of tape that is 50 meters long and 0.5mm thick.
I need to make a new roll that has an outside dimension of 800mm and an inside dimension of 700mm.
How many meters / rolls will it take to create the bigger roll and what is the formula.
I need to make a new roll that has an outside dimension of 800mm and an inside dimension of 700mm.
How many meters / rolls will it take to create the bigger roll and what is the formula.
#4
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Never been one for doing other people's homework...
Work out the area of the side of the roll of tape.
((800/2)^2 * pi)-((700/2)^2 * pi)
Now equate that to the area of tape. so the above expression = X mm of tape multiplied by 0.5mm.
Be careful with the units
Hope this is right. Been a long tome since I've done any maths
[Edited by dnb - 9/9/2002 7:57:33 PM]
[Edited by dnb - 9/9/2002 11:21:07 PM]
[Edited by dnb - 9/9/2002 11:36:38 PM]
Work out the area of the side of the roll of tape.
((800/2)^2 * pi)-((700/2)^2 * pi)
Now equate that to the area of tape. so the above expression = X mm of tape multiplied by 0.5mm.
Be careful with the units
Hope this is right. Been a long tome since I've done any maths
[Edited by dnb - 9/9/2002 7:57:33 PM]
[Edited by dnb - 9/9/2002 11:21:07 PM]
[Edited by dnb - 9/9/2002 11:36:38 PM]
#7
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Erm, dnb, it's not right.
And it can hardly be longer ago than my math courses.
Now come to the board, wipe away the wrong formula and write it again correctly.
Ralf
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#8
Now you have both lost me with the equations, its actually for a product I want to make at work.
The final thought is to get an accurate cost for something.
each small roll 5.5mm wide x 0.5mm thick x 50 meters costs $0.785
If I knew how to work out the Sq Inch cost I could calculate the final cost.
OD in Inches Divided by 2 X itself x 3.142 memory +
ID -------------------------"-------------- memory -
Memory recall = Total number of SQ Inches required.
So the price per Sq Inch is..................
The final thought is to get an accurate cost for something.
each small roll 5.5mm wide x 0.5mm thick x 50 meters costs $0.785
If I knew how to work out the Sq Inch cost I could calculate the final cost.
OD in Inches Divided by 2 X itself x 3.142 memory +
ID -------------------------"-------------- memory -
Memory recall = Total number of SQ Inches required.
So the price per Sq Inch is..................
#9
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Well, if the roll consist of 200 layers of tape (200*0,5=100 just as OD - ID; 800-700=100) with an average diameter of 750mm (as in (700+800)/2).
The formula for the circumference is diameter*pi
Multiply this with the number of mean layers
750mm * 200 * pi = 471.238,898mm = 471,239m
Pretty big roll of tape
Its cost would be: 0,785/50 = 0,0157 $/m multiplied with 471,239 m = 7,39845 $(Dollar?!)
You owe me a roll of tape, nah make that a beer!
Ralf
#12
Ralf, you are very clever, Are you saying the roll will have 200 layers knowing what the other dims are ? or is this just an example.
surely to make the bigger roll will not take 431,000 meters, maybe 431 would be more like it !
Yr helps appreciated.
surely to make the bigger roll will not take 431,000 meters, maybe 431 would be more like it !
Yr helps appreciated.
#13
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The roll will have 200 layers as one layer is 0,5 mm thick. 200 of them will bring the inner diameter of 700mm to 800mm (700 + (200*0,5) = 800)which are your requested dimensions.
Now you have the smallest diameter measuring 700mm * pi. The next layer would measure 700,5mm * pi, the next 701 * pi and so on another 198 times until 799,5 * pi and 800 * pi.
In this case, to save you the maths, you can assume that in the middle the circumference is 750 * pi and as the mean of all 200 layers you may replace all the 7xx,x measures with it. (Allowed here because the formula is simply 'diameter * pi' without any ^2 or so)
So you have 200 layers of tape at a medium diameter of 750mm (=0,750m).
This gives you 200* 0,75m *3,14 = 471 meters and 23 cm and 8 mm and a bit more.
Hope that helps
Ralf
Now you have the smallest diameter measuring 700mm * pi. The next layer would measure 700,5mm * pi, the next 701 * pi and so on another 198 times until 799,5 * pi and 800 * pi.
In this case, to save you the maths, you can assume that in the middle the circumference is 750 * pi and as the mean of all 200 layers you may replace all the 7xx,x measures with it. (Allowed here because the formula is simply 'diameter * pi' without any ^2 or so)
So you have 200 layers of tape at a medium diameter of 750mm (=0,750m).
This gives you 200* 0,75m *3,14 = 471 meters and 23 cm and 8 mm and a bit more.
Hope that helps
Ralf
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male.
I should be more careful with cut and pasting formulas. Oh well...
Was I right in assumuing the 50m * 0.5mm was the length and thickness of the unrolled tape?
I should be more careful with cut and pasting formulas. Oh well...
Was I right in assumuing the 50m * 0.5mm was the length and thickness of the unrolled tape?
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