Got another one for the maths bods
#1
Got another one for the maths bods
find all values of x from -pie<x<pie
of this equation
tanx=cosx
this is what i have got so far:
tanx=cosx
=>sinx/cosx=cosx
=>sinx=cos^2x
=>sinx=1-sin^2x
=>sin^2x+sinx-1=0
This is were i would like to factorise it but because of the difference in two squares it won't, so what do I do????
of this equation
tanx=cosx
this is what i have got so far:
tanx=cosx
=>sinx/cosx=cosx
=>sinx=cos^2x
=>sinx=1-sin^2x
=>sin^2x+sinx-1=0
This is were i would like to factorise it but because of the difference in two squares it won't, so what do I do????
#3
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well lets see, you have a tank, a pie, a sink, a sin and a cosie........
find a motor sport bod, ask him to fit your cosie engine in the tank, then bribe him with his sin full desire of pies, to make sure its doesnt sink.
How have I done???
O-level maths i got, knew it would come in handy one day
find a motor sport bod, ask him to fit your cosie engine in the tank, then bribe him with his sin full desire of pies, to make sure its doesnt sink.
How have I done???
O-level maths i got, knew it would come in handy one day
#4
Originally Posted by davegtt
u expect us to work that out at 4:45 on a friday afternoon? your avin a giraffe
#5
Your quadratic can be solved in the usual way
Substitute u=sin x
Quadratic is u^2 + u - 1 = 0
Solve for u = (-b +/- sqrt(b^2-4ac) / 2a
a = 1, b = 1, c = -1
u = (-1 +/- sqrt(5)) / 2
... which has two roots, u=0.6180 and u=-1.6180
x = arcsin u
which means (approx)
x = 0.6662
x = 1.5708 + 1.0613i
Substitute u=sin x
Quadratic is u^2 + u - 1 = 0
Solve for u = (-b +/- sqrt(b^2-4ac) / 2a
a = 1, b = 1, c = -1
u = (-1 +/- sqrt(5)) / 2
... which has two roots, u=0.6180 and u=-1.6180
x = arcsin u
which means (approx)
x = 0.6662
x = 1.5708 + 1.0613i
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