Somebody Check my Maths
02 August 2001, 08:16 PM
#1
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I'm trying to work out the average speed of Simons world record attempt.
Time is 2 Hours 11 minutes and 18 seconds.
= 131 minutes, 18 seconds.
time of lap is 30 seconds
lap length 408m
Therefore number of laps is 131*60+18=7878 seconds
7878/30=262.6 laps.
Distance travelled therefore is 107140.8m (262.7*408m) or 107.1408 Km
107.1408/7878=0.0136Km/Sec
0.0136Km/Sec*60=0.816Km/Min
0.816Km/Min*60=48.96/Km/hr
Average speed was <B>48.96Km/hr</B>
or <B>30.6Mph</B> (48.96/1.60)
Have I goofed??
[This message has been edited by Neil Smalley (edited 02 August 2001).]
Time is 2 Hours 11 minutes and 18 seconds.
= 131 minutes, 18 seconds.
time of lap is 30 seconds
lap length 408m
Therefore number of laps is 131*60+18=7878 seconds
7878/30=262.6 laps.
Distance travelled therefore is 107140.8m (262.7*408m) or 107.1408 Km
107.1408/7878=0.0136Km/Sec
0.0136Km/Sec*60=0.816Km/Min
0.816Km/Min*60=48.96/Km/hr
Average speed was <B>48.96Km/hr</B>
or <B>30.6Mph</B> (48.96/1.60)
Have I goofed??
[This message has been edited by Neil Smalley (edited 02 August 2001).]
02 August 2001, 09:33 PM
#3
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Neil,
Sounds about right. Car looked to be doing about 30mph around the circles. Saying that, Simon was seeing between 30 and 50mph on the speedo, but as that was wheel speed, not really relevant.
Cheers
Ian
Sounds about right. Car looked to be doing about 30mph around the circles. Saying that, Simon was seeing between 30 and 50mph on the speedo, but as that was wheel speed, not really relevant.
Cheers
Ian
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