I'm trying to work out the average speed of Simons world record attempt.

Time is 2 Hours 11 minutes and 18 seconds.
= 131 minutes, 18 seconds.

time of lap is 30 seconds
lap length 408m

Therefore number of laps is 131*60+18=7878 seconds
7878/30=262.6 laps.

Distance travelled therefore is 107140.8m (262.7*408m) or 107.1408 Km

107.1408/7878=0.0136Km/Sec
0.0136Km/Sec*60=0.816Km/Min
0.816Km/Min*60=48.96/Km/hr

Average speed was <B>48.96Km/hr</B>
or <B>30.6Mph</B> (48.96/1.60)

Have I goofed??


[This message has been edited by Neil Smalley (edited 02 August 2001).]

About right or near enough as we'll get it.

I worked on 29.5 sec laps & worked out a distance of just over 67 miles travelled, which would imply you're about bang on!

http://bbs.scoobynet.co.uk/smile.gif

Interested to find out the odometer's version...

Neil,

Sounds about right. Car looked to be doing about 30mph around the circles. Saying that, Simon was seeing between 30 and 50mph on the speedo, but as that was wheel speed, not really relevant. http://bbs.scoobynet.co.uk/biggrin.gif

Cheers

Ian