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Old 23 November 2011, 07:27 PM
  #31  
Turbotits
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I use a 10litre jerry can. 1 can when the tank is empty the fill with v power. I think thats about 16%. Thats how i had it mapped as its easy to measure
Old 23 November 2011, 07:53 PM
  #32  
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Originally Posted by Turbotits
I use a 10litre jerry can. 1 can when the tank is empty the fill with v power. I think thats about 16%. Thats how i had it mapped as its easy to measure
The trouble is with this route is you require the tank to be the same every time you fill, which is almost empty! As I was telling someone on here who pm'd me, is if using 20% mix to add a 5L jerry can to 20L of fuel, and ideally try and do this around 1/4 tank then at least you will get the right %. If you have 10L of fuel in your tank when you do your method, then the danger is you would actually be adding 10L of meth to 40L of fuel (60L tank), so you could actually be adding a 20% meth mix minus whatever the % ratio is of the original 10L mix. So your mapped for 16% but you could actually be running anything above 20% meth mix. You would need to run the tank very low to do your method, but if anyone is like me and live 7 miles away from a Shell or Tesco garage you would need to uneccesarily need to go out of your way to fill up when your nearing empty, where as at 1/4 tank to do a 5L meth / 20L fuel method wouldnt tie you down and would ensure an exact mix each time. Rob

Last edited by Rob Day; 23 November 2011 at 07:56 PM.
Old 23 November 2011, 08:07 PM
  #33  
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Originally Posted by Rob Day
The trouble is with this route is you require the tank to be the same every time you fill, which is almost empty! As I was telling someone on here who pm'd me, is if using 20% mix to add a 5L jerry can to 20L of fuel, and ideally try and do this around 1/4 tank then at least you will get the right %. If you have 10L of fuel in your tank when you do your method, then the danger is you would actually be adding 10L of meth to 40L of fuel (60L tank), so you could actually be adding a 20% meth mix minus whatever the % ratio is of the original 10L mix. So your mapped for 16% but you could actually be running anything above 20% meth mix. You would need to run the tank very low to do your method, but if anyone is like me and live 7 miles away from a Shell or Tesco garage you would need to uneccesarily need to go out of your way to fill up when your nearing empty, where as at 1/4 tank to do a 5L meth / 20L fuel method wouldnt tie you down and would ensure an exact mix each time. Rob
I agree with what your saying totally. In my case i live a mile away from a shell and tesco so dont have an issue there. I just let it go to fuel light every time i use meth. I dont use it perminantly so guess i dont get the problem of the mixture being to far out. I could ofcourse start using 10 litres meth to 40 litres petrol. Im due a map tweek soon. I dont think i want to be bothering with just a 25litre fill. It wouldnt get me far enough lol
Old 23 November 2011, 08:28 PM
  #34  
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This is what I'm planning on doing.
Obviously need to get the car to my mapper with as little fuel as possible. Will stick some VPower in the tank to get me there plus a can in the boot incase I run short on the way.

I am going to take a 24LT container of VPower with me and a container of 6LT methanol.
Will add both containers to the tank. This will be 30LT in total, 20% of which is methanol and 80% VPower.
Then map the car.

Sounds about right doesn't it ?

Then from then on just stick 24LT in at the station along with 6LT of methonal everytime.
Old 23 November 2011, 10:46 PM
  #35  
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Originally Posted by mazmike
yes m8 10% = ie 3 liters of methanol in tank then 30 liters of v max in after
Thats not 10%

3 litres of methanol and then 27 of v-power would be 10%


On topic Methanol is the cheapest way of a good power increase. Optimum seems to be 30% any more than that and the results are negligible
Old 23 November 2011, 11:14 PM
  #36  
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Originally Posted by MattyB1983
This is what I'm planning on doing.
Obviously need to get the car to my mapper with as little fuel as possible. Will stick some VPower in the tank to get me there plus a can in the boot incase I run short on the way.

I am going to take a 24LT container of VPower with me and a container of 6LT methanol.
Will add both containers to the tank. This will be 30LT in total, 20% of which is methanol and 80% VPower.
Then map the car.

Sounds about right doesn't it ?

Then from then on just stick 24LT in at the station along with 6LT of methonal everytime.
That sounds a complicated way of doing it.
Old 23 November 2011, 11:20 PM
  #37  
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Originally Posted by Ciaran
Thats not 10%

3 litres of methanol and then 27 of v-power would be 10%


On topic Methanol is the cheapest way of a good power increase. Optimum seems to be 30% any more than that and the results are negligible
sorry m8 but you are not right .10% is 1 part meth to 10 parts of fuel so 2 parts meth to 20 parts fuel so 3 part of meth is 30 fuel so total 33
Old 23 November 2011, 11:28 PM
  #38  
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Originally Posted by mazmike
sorry m8 but you are not right .10% is 1 part meth to 10 parts of fuel so 2 parts meth to 20 parts fuel so 3 part of meth is 30 fuel so total 33

10% methanol mix means 10% of the fuel in your tank is methanol and the rest (90%) is petrol.
If you have 30 LT in your tank then 10% of that is 3LT (meth) and 90% is 27LT (petrol).
Old 23 November 2011, 11:29 PM
  #39  
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Originally Posted by mazmike
sorry m8 but you are not right .10% is 1 part meth to 10 parts of fuel so 2 parts meth to 20 parts fuel so 3 part of meth is 30 fuel so total 33
No he is right, thats like saying 10 litres in a 110 tank is 10%. It's not. 10 litres in a 100 litre tank would be 10%, same rule applies here

30 plus 3 is a 10% increase

27 plus 3 would be 10% total
Old 23 November 2011, 11:29 PM
  #40  
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Originally Posted by Rob Day
That sounds a complicated way of doing it.
Suggest another way Rob please, first time running meth so am open to ideas.
Old 23 November 2011, 11:33 PM
  #41  
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Originally Posted by TH3_5T1G
No he is right, thats like saying 10 litres in a 110 tank is 10%. It's not. 10 litres in a 100 litre tank would be 10%, same rule applies here

30 plus 3 is a 10% increase

27 plus 3 would be 10% total
Surely when talking about a meth mix your calculations should be based on total amount of fuel and not how much you increase it by.
Old 23 November 2011, 11:38 PM
  #42  
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Let's say someone asks you to mix them up some, I don't know, filler. They want 500Grams of it but they tell you they want 10% of it to be hardener.

10% of 500 is 50, so you would mix up 450G of filler and 50G of hardener.
Old 24 November 2011, 10:00 AM
  #43  
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We tested 20% on our project car (relatively std 03 WRX) results were + 10% power and torque. Our version of 20% was 20% of the overall amount, eg 80/20 not 100/20. As long as you ensure you always mix the same amount it doesn't matter as long as it's the same as when mapped.
Old 24 November 2011, 10:41 AM
  #44  
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reading this i may be wrong
Old 24 November 2011, 10:56 AM
  #45  
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Originally Posted by MattyB1983
Let's say someone asks you to mix them up some, I don't know, filler. They want 500Grams of it but they tell you they want 10% of it to be hardener.

10% of 500 is 50, so you would mix up 450G of filler and 50G of hardener.
Matty my head's in a spin mate!

If you have 450g of filler don't you need to work on 10% of that therefore 45g of hardener?
Old 24 November 2011, 11:42 AM
  #46  
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If you want to run 20% methanol, you run 20% of the total volume in the tank.

So for an overall 50 litres of fuel you want 40 litres of V-Power, and 10 litres of meth.

For 25 litres overall you want a 5 litre jerry can with meth, measured out, as these things can take up to 7 litres, then put 20 litres V-Power on top.

Simples.
Old 24 November 2011, 11:42 AM
  #47  
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Originally Posted by Einstein RA
Matty my head's in a spin mate!

If you have 450g of filler don't you need to work on 10% of that therefore 45g of hardener?

When I'm mixing paint/clear coat if the amount is 500grams then it has 50grams of hardener added to make a total of 550.
It's 10% of the total fuel added ie 30 litres fuel=3 litres of meth=33 litres total.
Old 24 November 2011, 11:58 AM
  #48  
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Originally Posted by MattyB1983
Surely when talking about a meth mix your calculations should be based on total amount of fuel and not how much you increase it by.
That's what i was explaining

Saying that 33 with 3 lites of it being meth is increasing it by 10%, not being 10%. Therefore mazmike was wrong
Old 24 November 2011, 12:24 PM
  #49  
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I'm confused.

Let's say I want 30 liters of fuel in my car.
I require 20% of that total fuel to be methonal.
20% of 30liters is 6liters.
So I add 24liters of normal petrol and 6liters of methonal.

This will give me the 30litres total that I required, 20% of which is methanol.
Old 24 November 2011, 12:26 PM
  #50  
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Originally Posted by Einstein RA
Matty my head's in a spin mate!

If you have 450g of filler don't you need to work on 10% of that therefore 45g of hardener?
LOL.
My head is spinning to buddy...

My point was that the guy wanted a total of 500g. Including the hardener, probably not the best way to explain my point.
Old 24 November 2011, 01:57 PM
  #51  
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Originally Posted by MattyB1983
I'm confused.

Let's say I want 30 liters of fuel in my car.
I require 20% of that total fuel to be methonal.
20% of 30liters is 6liters.
So I add 24liters of normal petrol and 6liters of methonal.

This will give me the 30litres total that I required, 20% of which is methanol.
Right! I think I've got it finally
If working percentages say 20%, EITHER take the inclusive figure you want in the above case 30 litres and divide by 1.2. This will give the methanol content required for an overall volume of 30 litres which is 5 litres and then you add 25 litres of fuel.
OR
If you're taking the fuel quantity as a start figure then you multiply by 1.2 to give the methanol figure needed. For example if I add 25 litres of fuel I multiply 25 by 1.2 to give 30 and the difference is the amount of methanol I need to add, again 5 litres. This formula can be used for any percentage by changing the second digit.

Last edited by Maz; 24 November 2011 at 01:59 PM.
Old 24 November 2011, 02:47 PM
  #52  
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Originally Posted by MattyB1983
I'm confused.

Let's say I want 30 liters of fuel in my car.
I require 20% of that total fuel to be methonal.
20% of 30liters is 6liters.
So I add 24liters of normal petrol and 6liters of methonal.

This will give me the 30litres total that I required, 20% of which is methanol.
I was saying to mazmike hat you were right as he said you were wrong, not saying he was right.

Your right in your calcs, leave it at that lol
Old 24 November 2011, 02:50 PM
  #53  
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Originally Posted by Einstein RA
Right! I think I've got it finally
If working percentages say 20%, EITHER take the inclusive figure you want in the above case 30 litres and divide by 1.2. This will give the methanol content required for an overall volume of 30 litres which is 5 litres and then you add 25 litres of fuel.
OR
If you're taking the fuel quantity as a start figure then you multiply by 1.2 to give the methanol figure needed. For example if I add 25 litres of fuel I multiply 25 by 1.2 to give 30 and the difference is the amount of methanol I need to add, again 5 litres. This formula can be used for any percentage by changing the second digit.
Yes, 20% of, not on top of.

20% in a 30 litre tank = 6 litres meth and 24 petrol

20% in 50 litre tank = 10 litres meth and 40 petrol

20% in 60 litres = 12 litres meth and 48 petrol


And so on
Old 24 November 2011, 04:13 PM
  #54  
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This arguement is never going to end. Just get the car mapped to what you want it mapped to, but no greater than 20% (whatever that is) as there appears to be no worth (risk) gain beyond 20%. The continue to use what ever the "20%" is over and over regardless of this thread! However (LOL) I can see hoe people are conflicting the %. We are talking of running 20%, therefore it is 20% of the final mixture is meth, not 20% meth added to the original ingrediant (vpower).
Old 24 November 2011, 04:47 PM
  #55  
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Originally Posted by ScoobyDoo69
If you want to run 20% methanol, you run 20% of the total volume in the tank.

So for an overall 50 litres of fuel you want 40 litres of V-Power, and 10 litres of meth.

For 25 litres overall you want a 5 litre jerry can with meth, measured out, as these things can take up to 7 litres, then put 20 litres V-Power on top.

Simples.
What kind of cans are you talking about that can take up to 7 litres? I was mapped using one of these:
20 litre jerry can
with 16litres of v power then filled to the neck with meth i.e should be 4 litres of meth.
Then after that I have been using one of these:
5 litre can
a 5 litre can filled to the neck with meth and then another 20 litres of V-Power on top.
Old 24 November 2011, 05:59 PM
  #56  
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Pour in 2 five litres cans of methanol, then fill your tank to the top with petrol.

Thats your 20%.
Old 24 November 2011, 06:32 PM
  #57  
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Originally Posted by RA Dunk
Pour in 2 five litres cans of methanol, then fill your tank to the top with petrol.

Thats your 20%.
that depends on the tank size.
Old 24 November 2011, 07:04 PM
  #58  
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Originally Posted by RA Dunk
Pour in 2 five litres cans of methanol, then fill your tank to the top with petrol.

Thats your 20%.
Depends on tank size and how much fuel is already in the tank.
Old 24 November 2011, 07:20 PM
  #59  
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got mine mapped at 16% meths, 5 litres meths to 25 litres of fuel
Old 24 November 2011, 09:54 PM
  #60  
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Originally Posted by AbbasSTI
What kind of cans are you talking about that can take up to 7 litres? I was mapped using one of these:
20 litre jerry can
with 16litres of v power then filled to the neck with meth i.e should be 4 litres of meth.
Then after that I have been using one of these:
5 litre can
a 5 litre can filled to the neck with meth and then another 20 litres of V-Power on top.
A 5 litre filled to the neck will be much more than 5 litres...


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