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Calculating the volume of a toblerone shaped structure?

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Old 10 October 2010, 06:53 PM
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Dingdongler
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Default Calculating the volume of a toblerone shaped structure?
It's been a long time since I did geometry. I need to calculate the volume of a cylinder that is triangular in structure ie like a Toblerone.

Is it height x base x length divided by two?

Thanks
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Old 10 October 2010, 06:57 PM
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1/2 base x height x length
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Old 10 October 2010, 06:58 PM
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Originally Posted by Dingdongler
It's been a long time since I did geometry. I need to calculate the volume of a cylinder that is triangular in structure ie like a Toblerone.

Is it height x base x length divided by two?

Thanks
A cylinder is circle base tthough....
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Old 10 October 2010, 07:01 PM
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tony de wonderful
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Put it in water and record the displacement.
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Old 10 October 2010, 07:07 PM
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Originally Posted by tony de wonderful
Put it in water and record the displacement.
+1 for the Toblerone at least, the apex is curved and the additional segment gaps would render the standard method of calculation useless.
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Old 10 October 2010, 07:18 PM
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David Lock
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If above fails see if you can look up its density if it is a common material and weigh it?

dl
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Old 10 October 2010, 07:23 PM
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Sorry, it's not a cylinder then. Jaybird, it's not actually a bar of Toblerone mate with segments etc

Actually it's a roof structure that is triangular in shape.

I think pacenote is correct
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Old 10 October 2010, 07:24 PM
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john banks
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Melt the Toblerone, and as per the tag line of a user on here or some other forum, coat yourself in it and feed yourself to the lesbians. It might not give you the answer, but it could be a lot of fun.
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Old 10 October 2010, 07:26 PM
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Originally Posted by john banks
Melt the Toblerone, and as per the tag line of a user on here or some other forum, coat yourself in it and feed yourself to the lesbians. It might not give you the answer, but it could be a lot of fun.
Spent the whole weekend feeding myself to lesbians, bored of that now...
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Old 10 October 2010, 07:45 PM
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The volume of any regular shape is given by:

Cross sectional area x length.

In this case, the cross sectional area, it being a triangle, would be

1/2 x base x height
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Old 10 October 2010, 08:18 PM
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tony de wonderful
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Originally Posted by alcazar

In this case, the cross sectional area, it being a triangle, would be

1/2 x base x height
Only if it's equilateral.
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Old 10 October 2010, 10:46 PM
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Originally Posted by tony de wonderful
Only if it's equilateral.
doesn't matter if it's equilateral or not

area = 1/2 base x perpendicular height
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Old 11 October 2010, 08:57 AM
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Originally Posted by pacenote
doesn't matter if it's equilateral or not

area = 1/2 base x perpendicular height
Quite

What's equilateral got to do with it tony?
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Old 11 October 2010, 09:32 AM
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See here for a maffs lesson .... http://www.cimt.plymouth.ac.uk/proje...i9/bk7_9i5.htm

Sorry, no lesbian s3x involved!

Dave
 
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Old 11 October 2010, 10:14 AM
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Leslie
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Cross sectional area multiplied by length I imagine.

Les
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Old 11 October 2010, 10:26 AM
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Originally Posted by alcazar
The volume of any regular shape is given by:

Cross sectional area x length.

In this case, the cross sectional area, it being a triangle, would be

1/2 x base x height
+1 and no it doesn't matter whether the triangle is equilateral or not.
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Old 11 October 2010, 10:34 AM
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Originally Posted by tony de wonderful
Only if it's equilateral.
Incorrect - go to the bottom of the class!
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Old 11 October 2010, 11:04 AM
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All I know is that due to constant Father Day presents, I have quite a few on the top shelf in the kitchen going white
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Old 11 October 2010, 12:28 PM
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Leslie
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Originally Posted by Trout
Incorrect - go to the bottom of the class!
I doubt that he can now!

Les
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Old 11 October 2010, 04:19 PM
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Originally Posted by Trout
Incorrect - go to the bottom of the class!
He was already there
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