supernick

Can someone please explain to me how to work out this question?

Two cars are travelling in the same direction; one car is going at 30mph and the other is going at 50mph? If the first car is 10 miles ahead of the second car, how long will it take the second car to catch up with the first?

My mind is at a blank!!!

what would scooby do

20 MPH difference over 10 miles - not that hard to work out dude 30 mins?

DCI Gene Hunt

30 mins

ricardo

30 minutes.

After 30 minutes, car A (doing 50) will go 25 miles.
Car B (doing 30) will go 15 miles.

Since B started 10 ahead it will then be 25 miles from where A started, which is exactly where A is at that time.

BOB.T

Surely it's a Maths question, not Physics?

RobJenks

Assuming the first car is travelling at 30 mph

then

30 mph = 44 ft/sec

50mph = 73 ft/sec

Velocity difference = 29 ft/sec

Thus Time to catch up = Distance/velocity

= 10 x 5280/29 secs


= 1820 seconds or 30 miniutes

what would scooby do

LOL you don't half have to make things complicated.

The distance between the two cars is 10 miles and the speed difference is 20 MPH LOL

Now, what if the front car was an impreza and it had fuel surge for 5 seconds

Leslie

Its all relative really!

Les

Jay m A

iTrader: (2)

You're all wrong.



Its half an hour

davegtt

Half of a hour actually

what would scooby do

half of which hour exactly ?

davegtt

Half of the hour after they set off

speedking

The second car will never catch up. By the time he has done 10 miles (1/5 hour) the first car will have covered a further 30/5 = 6 miles. When the second car has done the 6 miles (6/50 hours) the first will have moved 180/50 = 3.6 miles, and so ad infinitum

windyboy

The one being driven by the girl will never catch up
<dons flameproof jacket and runs away to hide>

Windyboy.

Luminous

iTrader: (3)

yes, yes, but what If one of the gets a remap?