Big Daz

I am looking for help in creating a program which takes a number and continuisly divides the answer by 2 until the difference is less than 0.00005.
Can any Computer experts help me ( pretty computer illiterate )?

Cheers

Big Daz

Big Daz

Sorry, realised posted in wrong forum. Can a Mod move this for me please.
Ta

Big daz

Dan B

Somthing like this:

While result not equal to 0.000005 divide previous result by 2

printf: "now you just need to code it "

Katana

Hehe nice try. I tried to do the same by getting Andy F to do my homework too without joy.

BoxerFlat4

float PointlessFunction( float Value )
{
while( Value > 0.00005 )
{
Value = Value / 2.0f;
}
return Value;
}

Tomorrow, we will be explaining polymorphism....

Big Daz

Homework, Who mentioned Homework !!
Can paint pretty pictures and calculate train fares, just can't get my head round this. Maybe better just carry on with what I get paid for.

sooby

BoxerFlat4,

Don't you have to make that a class to make it C++?

BoxerFlat4

It'll compile under C++ : remember, C is just a subset of C++.

If you wanted to be clever :-

class DefineDivisionClass
{
// Class Variable
float m_Value;

// Constructor
void DefineDivisionClass( float value )
{
m_Value = value;
while( m_Value > 0.0005 )
{ m_Value = m_Value / 0.5f; }
}

// Destructor
~DefineDivisionClass ()

// Access Value variable
float GetValue( void )
{ return m_Value; }
{};

// Member functions

};

{
.
.
.
DefineDivisionClass TheClass( 2.0 );
float result = TheClass.GetResult();
.
.
.
}

Big Daz

Ooooohhh what have I started here !! (feel head getting ready to explode)

Dan B

Use a spreadsheet 10 times quicker...

MrDeference

static int CMyClass::GetIteratedAmount(int x)
{
int count = 0;
while ((20000 * x) > (2<<count))
{
count ++;
}
return count;
}

Rob Walker

spot the bug time

// Constructor
void DefineDivisionClass( float value )
{
m_Value = value;
while( m_Value > 0.0005 )
{ m_Value = m_Value * 0.5f; } // should be * 0.5 rather than / 0.5
}

MorayMackenzie

Re: "It'll compile under C++ : remember, C is just a subset of C++."

Hum.

C arrived first, by many years.

C++ is mostly a superset of C, mostly.


Moray

(thinks: " for ( ; value > 0.00005 ; value/=2.0F ){}; " )

MrDeference

Since we are bug fixing...
As long as the number is a whole number between 1 and 214747 mine's the quickest.
If the number has to be a decimal or out of those bounds change the parameter to a double and it's still quickest.
:P

[EDIT] Actually it dawns on me that I am solving a different problem to everyone else PMSL.
Before I go back to sleep is the final value important or did you just want the count?

[Edited by MrDeference - 3/26/2003 5:28:22 PM]

stevencotton

It'd be even faster without the inital "2<<0" surely

MrDeference

Well, yeah.
You know I have been sat here looking at it, and it's only algebra. Something that could be solved with a one hit equation. No iteration, nothing.
Can I work out what it is? Nope.