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Old 26 October 2010, 09:55 PM
  #271  
typeRv4
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I think you are confused, thats not how you measure efficiency. In fact im not sure what its measures.

By your logic if ambient temperature were 2 C and the post intercooler temps were 3 C, we could say its gone up by 50% lol

The correct way to measure intercooler thermal efficiency is thus

(Intercooler temp input - Intercooler temp output ) / ( Intercooler temp input - ambient temp) =

(138 - 32.5) / (138 - 21) = 90%
Old 27 October 2010, 08:33 AM
  #272  
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Are those temperature shots taken at idle when stationary?
Old 27 October 2010, 08:48 AM
  #273  
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um 50% because the difference of 10 degrees (30-20, i rounded it) is 50% of the initial figure of 20.

the higher the inlet temps go the more power you loose. the temp change shows that inlet temps have gone up by 50%, so power loss, due to temps will be 50% greater than the first pics. But 50% is not 50% power loss, its just 50% additional loss through thermal expansion of air. i can't remember what the figure is for bhp loss for degrees C increase in inlet temps off the top of my head.
Old 27 October 2010, 09:51 AM
  #274  
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Originally Posted by Tidgy
um 50% because the difference of 10 degrees (30-20, i rounded it) is 50% of the initial figure of 20.
Nope, the efficiency is based on the turbo out temperature, not just the difference between inlet and charge temps.

Look at the formula TypeRv4 has given.
Old 27 October 2010, 07:34 PM
  #275  
typeRv4
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Originally Posted by Butty
Are those temperature shots taken at idle when stationary?
Those shots were taken as the car was moving by an assistant.
Old 27 October 2010, 07:54 PM
  #276  
typeRv4
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To quote Harvey

Originally Posted by harvey
The objective is to get the air entering the inlet manifold at the throttle body as close to ambient temperature as possible.With an efficient front mount that temperature will typically be 6-12 degrees over ambient so let us assume your in car temperature guage is showing 16 degrees then you could expect to see 22-28 degrees on your ACT guage.
In this case if you just measured % gains on the movement of air temps on a good fmic you could say 37-75% - which of course is nonsense.

We normally refer to air charge temperatures as "X" degrees over the ambient.
Rather than worry about efficiency its more important to measure the amount degrees over ambient.

According to the above a good FMIC does 6-12 degrees over ambient @ WOT.

My test shows in this case 11.5 degrees over ambient. So not quite as good as a FMIC but pretty close.

It helps this test was done on the road to get real world airflow thru the tmic and i run a big scoop.

I hope to do some more tests with a watersprayer.

Last edited by typeRv4; 11 November 2010 at 02:26 AM. Reason: added WOT
Old 28 October 2010, 08:11 AM
  #277  
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The figures above refer to temperatures over ambient on wide open throttle, either on the road or at the end of a rolling road session where we measure the peak on power.
Old 28 October 2010, 08:17 AM
  #278  
Tidgy
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ah sorry i get ya, i think i'm getting my wires crossed lol
Old 11 November 2010, 02:24 AM
  #279  
typeRv4
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Retested the same classic hyperflow top mount with waterspray.

Left is air temp before the airbox, right is exiting the intercooler.

1.7bar peak - md321. Test on exactly the same road.

Temperature increase over ambient 7.1C,

not bad for a top mount

Last edited by typeRv4; 11 November 2010 at 02:27 AM.
Old 11 November 2010, 03:28 PM
  #280  
lunar tick
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Originally Posted by typeRv4


Temperature increase over ambient 7.1C,

not bad for a top mount
I would be careful Type R4 - all this talk of TMICs doing a decent job wll have the 'FMIC thought police' after you...
Old 11 November 2010, 03:34 PM
  #281  
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Originally Posted by Tidgy
so in one run it gone up 50%, mmm so much for efficient top mounts lol



The % rise in actual temperature should be calculated using the Kelvin scale - ie 11.5/(273 + 21) = 0.039% - not quite 50%!!
Old 11 November 2010, 03:45 PM
  #282  
Tidgy
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Originally Posted by lunar tick


The % rise in actual temperature should be calculated using the Kelvin scale - ie 11.5/(273 + 21) = 0.039% - not quite 50%!!

christ if you realy wanna get that pissy about it.

lets simplify it,

hotter = bad
colder = good

the temps have gone therefore its bad
Old 11 November 2010, 06:14 PM
  #283  
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Originally Posted by lunar tick


The % rise in actual temperature should be calculated using the Kelvin scale - ie 11.5/(273 + 21) = 0.039% - not quite 50%!!
<cough> multiple by 100 </cough>

3.9%
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