Just finished testing my new setup.
Pagid RS 421 pads and Prodrive discs (on MY00 4pots).
We used a GPS datalogger and did 10 tests from 60-0.
1. 3.28
2. 2.76
3. 2.75
4. 2.66
4. 2.63
6. 2.69
7. 2.80
8. 2.71
9. 2.74
10. 2.69

The logger gave a "blip" when hitting 60 so the only variable is my right foot.
How can I translate this in braking power ?
Is there a formula for it or something to compare with ?

Creepy

PS : the first time is slower because the brakes where a little on the cold side !

add them all up and divide by 10 thats your mean answer.just done it and its 2.771 so from 0-60 on average will take 2.771 secshttps://www.emotipad.com/emoticons/Clever.gif

That one I already knew.
I just want this numbers compare with something..
Is there a way to calculate the G-force out of this ?
Or is there anyway to compare this with braking force from other cars ?

Creepy

If you make the assumption (possibly flawed ;)) that you have uniform deceleration, then you can use the uniform acceleration equations to work out the acceleration and F=ma to work out the force. These will, of course be rough averages...

http://www.physchem.co.za/Graphs/Equations.htm

I hill climb my STI, and we measure to 1/100th of a second the start line 'G. There is a light beam at the start and one set at exactly 64 feet on from the start beam. If you cut the 64 ft beam in 2 seconds it equals 1 G accelleration.( 1 G is 32 ft/sec)
My STi on Kumho's and 314 bhp does the 64 in 2.06 secs.
Just maybe this will help?
A good EVO will do the same in 1.9secs, and there is an AUDI Quattro which will pull 1.7 secs!!!!!!!!!!!!!!!!!
Dream on.
Graham.

911,

Not having a go but I don't understand the 64' after two seconds thing.

Gravity is 9.8 metres per second, per second, which is approx. 32fp/s/s.

If you instantly started accelerating at 1G, you'd do 32' in one second, and 64' in the second second, a total of 96' after two seconds.

Vindaloo.

Guy's were moing off topic here,
I just wanna know what the G-force is when braking at the above times.....

Creepy

Assuming linear deceleration (which is not right :)) then a=v/t = 26.66666/2.63 = 10.12 m/s/s

Which is about 1.03g (assuming 1g is 9.81 m/s/s)

pretty impressive m8tee
shame u gits dont know anything bout wheel bearings:p
lol

Glenn, you mention linear declaration (wich is not right), what sort of deviation are we talking about here ?
1.03 G is pretty impressive (personal speaking), but I think it's more in the 0.9-0.95 G...

Creepy (anyway, the car brakes good)