My maths is a bit rusty, can anyone help?
If A has a 90% chance of happening, B has a 80% chance of happening and C, 70% Then the chances of A AND B happening are 90%*80% = 72% and likewise for A AND C, 90%*70% = 63% However what are the chances of A happening AND (either B OR C)? What is the maths behind that one? |
Ouch, mine's rusty too. Something to do with Bayes Theorem, I think.
Anyway, here's an 'interesting' page on probability that might help: http://www.stats.gla.ac.uk/steps/glossary/probability.html |
You have to think about it backwards: there are four combinations of B and C
1) B and C both happen 2) B happens but C doesn't 3) C happens but B doesn't 4) Neither B nor C happen. You want to capture the first three cases (I assume by 'or' you mean 'OR' not 'XOR'), so the probability of that is 100% minus the probability that neither happen, which is 1-(.2*.3)=.94 or 94%. Then multiply by the probability of A (90%) to get A AND (B OR C) as 84.6%. You could also do the same by summing the first three cases, but it takes longer that way. [Edited by carl - 4/17/2002 11:19:40 AM] |
I was gonna say that but Carl beat me to it! ;)
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what if it rains? will it still happen?
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that doesn't sound right to me.
if a and b have a 70% chance of happening A and C have a 60% chance of happening how can the chances of either of these happeing together be MORE than the chance of one happening on it's own? |
The chance of B OR C happening is far greater than the chance of one of them happening.
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Matt you are saying what if A (AND) B happen Carl is saying if A ( OR ) B happen - totally different .....
its all to do with the OR statement |
disagree - it says A and (B or C)
i.e. A and B and C would not count therefore it's 90%x(24%+14%) = 34.2% (B not C is 80% x 30% = 24%) (C not B is 70% x 20% = 14%) (generally in questions like this they're kept simple hence XOR is never used, they would have put 'and or' instead of 'or' if both B and C could apply in addition to A) isn't maths fun! :) Gordo [Edited by Gordo - 4/17/2002 7:17:31 PM] |
whichever way its read .. he now has all the possible answers he could of wanted !! :D
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