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scooby_si 20 March 2004 04:09 PM

a puzzle i need help with?
 
Mate has just set me a puzzle which he has been set by someone else & i couldn't see an obvious answer straight away so just thought i'd ask on here if anyone has come across it &/or knows the answer before i try racking my brain if it's not possible of sumin....;)
Anyway it goes like this:

you have 12 identical looking metal balls (bearings wotever). 11 are exactly the same weight & the 12th isn't maybe lighter or heavier.
You have a set of scales. You can use them 3 times with any combination of the balls on them at any time.
After the 3 uses of scales you have to distinguish which ball is different & whether it's heavier or lighter than the others. HOW?

Any cunning plans/solutions folks?
Ta
Si

PuzzleSolver 20 March 2004 04:26 PM

GOT IT!!

You take the 12 balls and split them into 2 giving 6 each!!

Put the 2 groups of six on the scales!! whichever is heaviest keep and discard the other 6

Now your left with 6!! split into 2 groups giving 3 each group!!

Put the 2 groups on the scales! whichever is heaviest keep, discard the other group!!

You are now left with 3 balls

Split into 3! put 1 on each side of the scales and keep 1 to one side!

If your scales are eqaul then the ball you put to the side is heavier/lighter

But i cant flippen figure out how to distinguish which!

Anyone help??

mj 20 March 2004 04:30 PM


You are now left with 3 balls

Split into 3! put 1 on each side of the scales and keep 1 to one side!
put any two of the three balls on the scales.

if the scales balance you have the heaviest ball in your hand.

if the scales don't balance then...:)

ScoobyTal 20 March 2004 04:37 PM

cool

PuzzleSolver 20 March 2004 04:38 PM


Originally Posted by mj
put any two of the three balls on the scales.

if the scales balance you have the heaviest ball in your hand.

if the scales don't balance then...:)


But you need to know whether its heavier or lightier so my theory is completly wrong!!

Need to start again

what would scooby do 20 March 2004 04:39 PM

Weigh 1, 2, 3, 4 vs 5, 6, 7, 8 with 3 possible outcomes:-

1/ If they balance then 9,10,11,12 have the odd ball, so weigh 6,7,8 vs 9,10,11 with 3 possible outcomes:-
i/ If 6,7,8 vs 9,10,11 balances, 12 is the odd ball. Weigh it against any other ball to determine if heavy or light.
ii/ If 9,10,11 is heavy then they contain a heavy ball. Weigh 9 vs 10, if balanced then 11 is the odd heavy ball, else the heavier of 9 or 10 is the odd heavy ball.
iii/ If 9,10,11 is light then they contain a light ball. Weigh 9 vs 10, if balanced then 11 is the odd light ball, else the lighter of 9 or 10 is the odd light ball.

2/ If 5,6,7,8 > 1,2,3,4 then either 5,6,7,8 contains a heavy ball or 1,2,3,4 contains a light ball so weigh 1,2,5 vs 3,6,12 with 3 possible outcomes:-
i/ If 1,2,5 vs 3,6,12 balances, then either 4 is the odd light ball or 7 or 8 is the odd heavy ball. Weigh 7 vs 8, if they balance then 4 is the odd light ball, or the heaviest of 7 vs 8 is the odd heavy ball.
ii/ If 3,6,12 is heavy then either 6 is the odd heavy ball or 1 or 2 is the odd light ball. Weigh 1 vs 2, if balanced then 6 is the odd heavy ball, or the lighest of 1 vs 2 is the odd light ball.
iii/ If 3,6,12 is light then either 3 is light or 5 is heavy. Weigh 3 against any other ball, if balanced then 5 is the odd heavy ball else 3 is the odd light ball.

3/ If 1,2,3,4 > 5,6,7,8 then either 1,2,3,4 contains a heavy ball or 5,6,7,8 contains a light ball so weigh 5,6,1 vs 7,2,12 with 3 possible outcomes:-
i/ If 5,6,1 vs 7,2,12 balances, then either 8 is the odd light ball or 3 or 4 is the odd heavy ball. Weigh 3 vs 4, if they balance then 8 is the odd light ball, or the heaviest of 3 vs 4 is the odd heavy ball.
ii/ If 7,2,12 is heavy then either 2 is the odd heavy ball or 5 or 6 is the odd light ball. Weigh 5 vs 6, if balanced then 2 is the odd heavy ball, or the lighest of 5 vs 6 is the odd light ball.

iii/ If 7,2,12 is light then either 7 is light or 1 is heavy. Weigh 7 against any other ball, if balanced then 1 is the odd heavy ball else 7 is the odd light ball.

mj 20 March 2004 04:40 PM

bollocks,

1 - 6 in each.
2 - 3 in each.
3 - 1 in each.

muppet:)

mj 20 March 2004 04:42 PM

spoke too soon...I missed the "lighter bit":o

what would scooby do 20 March 2004 04:44 PM

LOL

scooby_si 20 March 2004 04:55 PM

PMSL that's nothing i was thinking in new money where it's a set of scales which just tells you weight of wots on it rather than the balancing variety, doh explains why i was thinking it maybe impossible ;) lmfao
Si

Bluie 20 March 2004 05:32 PM

You will know if heavier or lighter when you first weigh the 6 balls against the other 6 balls, then split as mentioned above

Nick

scooby_si 20 March 2004 06:58 PM

that wouldnt work thou as you would only know one set of 6 was lighter or heavier than the other you wouldn't be able to know which group contained the odd ball & thus you would know nothing about any specific set of balls & thus not be able to eliminate down to 1 in 2 more usages so WWSD's description is the only way i can see as such, where did you get it from? ;)
Si

what would scooby do 20 March 2004 07:02 PM

STFI is what I did ;)

scooby_si 20 March 2004 07:09 PM

eeew thats a new un on me hang on i think i can solve it erm ahh "search the f3kin internet"? :eek: pmsl
Si

mj 20 March 2004 07:22 PM

Owned (nearly) :D

...forget ye old fashioned balancing scales.....


pick 6 random balls and weigh them.

multiply the figure by 2, then divide by 12, you now have the weight of the average ball across the two packs of 6, assuming all balls weigh the same.

say the balls are "100g" each.


back to reading on the scales....................


650g + , you have the odd ball and it's heavier.

less than 550g you have the odd ball and its lighter.

You *should* not get a weight inbetween 550 and 650, it ill either be above or below.


2 more goes on the scales............:eek:


..lets say your fist weigh said 537, so we assume its got the lightweight oddball.....[mj's theory of weighabilty] the mid point of 12x100g average balls is 600g, the difference +/- of this figure will be the weight of the oddball multiplied by 2, thusly :rolleyes: the oddball is (600-537)x2=126g for the oddball.[/mj's theory of weighabilty]

pick 3 random balls and weigh them.

multiply the figure by 2, then divide by 6, you now have the weight of the average ball across the two packs of 3.

back to reading on the scales....



350g + , you have the odd ball and it's heavier.

less than 250g you have the odd ball and its lighter.

You *should* not get a weight inbetween 250g and 350g, it ill either be above or below.


1 more go on the scales...:eek:x2:

..You have 3 balls (ET) ;) ).





...over to you puzzle solvers, I'm too pissed. :)

f1 20 March 2004 07:24 PM

is this not just a trick question ??? Why don't you pick each ball up in turn and you'll feel the heavier / lighter ball. Where does it say you HAVE to use the scales ???

mj 20 March 2004 07:38 PM

Ignore my last post..the answer to the question is that it can't be done. :(

Spoon 20 March 2004 07:55 PM

I ask you!!
 
Throw the scales in the bin and just look at the weights stamped on the fúckers.

PuzzleSolver 21 March 2004 02:01 PM

F1!!! I think you just got it!! Take my method from earlier on! Find the odd ball then use your hands to weigh and distinguish whether it is heavier or lighter.

mj 21 March 2004 03:31 PM

that wont work unless its significantly heavier or lighter.

Bonehead 22 March 2004 10:32 PM

has anyone got the answer yet?

Tim66 STi8 22 March 2004 10:59 PM

Here's a long shot, Get some flour in a 4" tray & drop each ball 1 at a time from the same height & measure the crator & depth 11 should be the same & 1 diferrent. It may not be the correct answer but it should work. :D


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